TypeError Exception in Python

The TypeError Exception in Python is raised when you try to apply any operation or function call to an inappropriate type of object.

For example -

1. Trying to concatenate a list and a number
2. Calling a variable as a function
3. Passing an argument to a function of the wrong type etc.

Example 1

Code/Output

# concatenating list with an integer
x = [1, 2, 3]
y = 2

print(x+y)
>>> TypeError: can only concatenate list (not "int") to list

# passing an unsupported index
x = [1, 2, 3]
print(x[0.5])
>>> TypeError: list indices must be integers or slices, not float

# calling a variable as a function
x = "Pylenin"
x()
>>> TypeError: 'str' object is not callable

# Passing wrong argument
def addition(x, y):
    return x+y

print(addition(10, [1, 2]))
>>> TypeError: unsupported operand type(s) for +: 'int' and 'list'

You can handle these errors using the TypeError Exception class.

Example 2

Code

# concatenating list with an integer
x = [1, 2, 3]
y = 2
try:
    print(x+y)
except TypeError as e:
    print(f"TypeError handled."
          f"Error reason - {e}")

# passing an unsupported index
x = [1, 2, 3]
try:
    print(x[0.5])
except TypeError as e:
    print(f"TypeError handled."
          f"Error reason - {e}")


# calling a variable as a function
x = "Pylenin"
try:
    x()
except TypeError as e:
    print(f"TypeError handled."
          f"Error reason - {e}")


# Passing wrong argument
def addition(x, y):
    return x+y

try:
    print(addition(10, [1, 2]))
except TypeError as e:
    print(f"TypeError handled."
          f"Error reason - {e}")

Output

TypeError handled.Error reason - can only concatenate list (not "int") to list
TypeError handled.Error reason - list indices must be integers or slices, not float
TypeError handled.Error reason - 'str' object is not callable
TypeError handled.Error reason - unsupported operand type(s) for +: 'int' and 'list'

Check out other Python Built-in Exception classes in Python.

built-in-exception-classes - Pylenin

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